# Find the length of the dril bits in different size?

**URL:** <https://forum.opencv.org/t/find-the-length-of-the-dril-bits-in-different-size/9667>\
**Category:** Python\
**Created:** [July 28, 2022, 12:12pm UTC](https://forum.opencv.org/t/find-the-length-of-the-dril-bits-in-different-size/9667 "2022-07-28T12:12:00Z")\
**Posts on this page:** 5\
**Page:** 1

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**Author:** ![Nfsrajesh2016](https://avatars.discourse-cdn.com/v4/letter/n/47e85d/32.png) [@Nfsrajesh2016](https://forum.opencv.org/u/Nfsrajesh2016)\
**Post date:** [July 28, 2022, 12:12pm UTC](https://forum.opencv.org/t/find-the-length-of-the-dril-bits-in-different-size/9667/1 "2022-07-28T12:12:00Z")

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I want to find the length of the dril bit

I try some way that result not accurate value and if i change the dril bits image to another size that the time that program not work

![condril](https://us1.discourse-cdn.com/flex020/uploads/opencv/original/2X/c/c6ac0ed56d519940f1b3fa749a00d1f0063771d9.png)

This dril bit size is 5mm is actual size are 3.4  
My program

```auto
import cv2
import numpy as np
image=cv2.imread('dril1.png',0)
ret,thresh = cv2.threshold(image,127, 255,0)
contours,hierarchy=cv2.findContours(thresh,2,1)
cnt=contours[13]
x,y,w,h=cv2.boundingRect(cnt)
rect=cv2.minAreaRect(cnt)
cv2.rectangle(image,(x,y),(x+w,y+h),(0,0,127),2)
cv2.circle(image,(int(rect[0][0]),int(rect[0][1])), 5, (255,0,0), -1)
cv2.putText(image, f'Width : {int(rect[1][0])}',(int(rect[0][0]),int(rect[0][1])),cv2.FONT_HERSHEY_SIMPLEX,0.6,(255,0,0),1, cv2.LINE_AA)
cv2.putText(image, f'Height : {int(rect[1][1])}',(int(rect[0][0]),int(rect[0][1])-20),cv2.FONT_HERSHEY_SIMPLEX,0.6,(255,0,0),1, cv2.LINE_AA)
cv2.imshow('img',image)
cv2.imwrite('drill.png',image)
cv2.waitKey(0)
cv2.destroyAllWindows()

```

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<div class="post-metadata">

**Author:** ![crackwitz](https://sea2.discourse-cdn.com/flex020/user_avatar/forum.opencv.org/crackwitz/32/14_2.png) [@crackwitz](https://forum.opencv.org/u/crackwitz)\
**Post date:** [July 28, 2022, 12:52pm UTC](https://forum.opencv.org/t/find-the-length-of-the-dril-bits-in-different-size/9667/2 "2022-07-28T12:52:00Z")

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related:

> <https://stackoverflow.com/questions/73137625/how-to-measure-the-drill-bit-using-opencv-python>

> <https://stackoverflow.com/questions/73137625/how-to-measure-the-drill-bit-using-opencv-python>

> <https://stackoverflow.com/questions/73150239/how-to-find-reference-point-in-a-object-for-measurement-purpose-using-opencv-pyt>

> <https://stackoverflow.com/questions/73161582/how-to-measure-the-length-of-the-object-using-opencv-python>

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<div class="post-metadata">

**Author:** ![Nfsrajesh2016](https://avatars.discourse-cdn.com/v4/letter/n/47e85d/32.png) [@Nfsrajesh2016](https://forum.opencv.org/u/Nfsrajesh2016)\
**Post date:** [July 28, 2022, 12:09pm UTC](https://forum.opencv.org/t/find-the-length-of-the-dril-bits-in-different-size/9667/3 "2022-07-28T12:09:00Z")

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I want to find the length of the dril bit

I try some way that result not accurate value and if i change the dril bits image to another size that the time that program not work

![condril](https://us1.discourse-cdn.com/flex020/uploads/opencv/original/2X/c/c6ac0ed56d519940f1b3fa749a00d1f0063771d9.png)

This dril bit size is 5mm is actual size are 3.4225 inches.

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<div class="post-metadata">

**Author:** ![Nfsrajesh2016](https://avatars.discourse-cdn.com/v4/letter/n/47e85d/32.png) [@Nfsrajesh2016](https://forum.opencv.org/u/Nfsrajesh2016)\
**Post date:** [August 3, 2022, 12:12pm UTC](https://forum.opencv.org/t/find-the-length-of-the-dril-bits-in-different-size/9667/4 "2022-08-03T12:12:35Z")

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i raised the same question into stack over flow but no one can reply this. so i ask in opencv community.

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<div class="post-metadata">

**Author:** ![crackwitz](https://sea2.discourse-cdn.com/flex020/user_avatar/forum.opencv.org/crackwitz/32/14_2.png) [@crackwitz](https://forum.opencv.org/u/crackwitz)\
**Post date:** [August 3, 2022, 3:38pm UTC](https://forum.opencv.org/t/find-the-length-of-the-dril-bits-in-different-size/9667/5 "2022-08-03T15:38:14Z")

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that’s because you keep ignoring what people tell you, and you appear to expend no mental effort at all on understanding the high school math behind the problem. there’s no way to be more diplomatic about that. this task might just be beyond your capabilities, and nobody has any reason to just hand you the solution. it’s clearly a commercial application that you try to earn your living with. time to reconsider.