Homography (mathematic) question

So. Someone helped me … I think she found the solution. I need two flip matrix to handle the two different sizes:

    Mat F1 = Mat::eye(3, 3, CV_64FC1);
    F1.at<double>(1,1) = -1.0;
    F1.at<double>(1,2) = source_ry - 1.0;

    Mat F2 = Mat::eye(3, 3, CV_64FC1);
    F2.at<double>(1,1) = -1.0;
    F2.at<double>(1,2) = target_ry - 1.0;

    H = F2.inv() * H * F1;