Basic image information

Python
6

Hello.
It is the exact same image file, it is an indexed TIFF file which this forum engine forbids to upload unfortunately. I made test code in both C++ and Python:

C++

#include <opencv.hpp>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
    cv::Mat input_image;
    cv::Size size;
    int numChannels = 0;
    string imageFile = "test.tif";

    input_image = cv::imread(imageFile, -1);
    if (input_image.data == NULL)
    {
        cout << "Could not open file " << imageFile << endl;
        return -1;
    }

    size = input_image.size();
    numChannels = input_image.channels();

    cout << imageFile << ": height=" << size.height << ", width=" << size.width << ", channels=" << numChannels << endl;

    return 0;
}

And Python:

import sys
import cv2

if __name__ == "__main__":
    imageFile="test.tif"
    inputImage = None

    try:
        inputImage = cv2.imread(imageFile, -1)
        if inputImage is None:
            print("Could not load image.")
            exit()
    except Exception as e:
        print("Exception - ",str(e))
        exit()
    imgHeight, imgWidth, numChannels = inputImage.shape
    print(f"{imageFile}: height={imgHeight}, width={imgWidth}, channels={numChannels}")
exit()

Output from C++:

test.tif: height=512, width=512, channels=1

Output from Python:

test.tif: height=512, width=512, channels=3